Math problems Essay Example | Topics and Well Written Essays - 1500 words

Math problems - Essay Exampleii) -1.89 lie in IR region. 1c)Because its closer to the nucleus and having some effect on the other electron present in the higher shell Q2 a) Power output of sun = 3.8 *1026W Radius = 1.4 * 108 Power density = ? V= 4/3 ?r3 V= 4/3 ? (1.4*108)3 =1.15*1025 Power density Power/volume = 3.8*1026/1.15*1025 1ev= 1.6*10-19J Total null released for He nucleus is 26.7 Mev 26.7*106*1.6*10-19 4.27*10-12 energy is released for 1 he molecule =3.8*1026 J produce 3.8*1026/4.27*10-12 *1/(4*?*(1.4*108)3/3) atomic number 2 atoms per second per third-dimensional meter (here assume time =1sec there fore energy =3.8 *1026W *1sec 7.74*1012 Helium atoms per second per cubic meter 2b) In He both the nucleons are there means protons and neutron,2 protons and 1 neutron is there. In first of all equation there are less number of nucleons involve so there nuclear contract will be less and thus it will be more reactive there fore they are less stable while on the other hand wh en the nucleons are more in number as it is in step 2 therefore there will be hearty nuclear force, will be less reactive and more stable. 2c) When the fusion reaction occurs so at that time two atoms combine and produce larger atom and release high energy in the form of binding energy of nucleons. As this process continues till the formation of iron Fe 56,so at that time binding energy of electron is minimum that is most negative and now if the more heavier atom is required to be formed so more energy will release Q3 a i) data Red shift key = z = 0.13 Speed of light =c= 3 * 108 ms-1 Hubble constant = H0 = 70 kms-1Mpc-1 Distance to the galaxy = r=? Formula 1. H0 = v / r Here v = apparent speed of galaxy 2. v = z * c Solution v = z * c =0.13 * 3 * 108 v = 3.9 * 107 ms-1 v = 3.9*107*10-3kms-1 v = 3.9*104 kms-1 H0 = v / r r= v / H0 r = 3.9*104 /70 r = 5.57*102 Mpc Q3 a ii) Data Red shift =z = 0.13 ?0=589nm ?1=? Formula =?1-?0 z=/?0 Solution z= /?0 0.13= /589 =76.57nm ?1-?0 =76.57 ?1 =76.57+589 ?1=665.57nm ?1=6.65*102 nm Q3 b i) As the wavelength of divinatory object is diverse as compare to the wavelength of the objects which are already present in the cluster and this wavelength is very large which causes this hypothetical object to move out of the galaxy thats why that this object is not part of this cluster, and is genuinely more distant. Q3 b ii) The answer is not in the book. Or no relative material is in the book kindly search yourself Q4 common relativity and quantum gravity depart from Newtons theory. The gravitational force of attraction is described by Newtons law of gravity. Einsteins theory of commonplace relativity describes the interaction between space and the matter within it. When the masses construct very large, this theory provides a more accurate description of gravity than does Newtons law. General relativity also predicts the existence of gravitational radiation, which is emitted by massive objects that undergo an acceleration. There is good manifest that such radiation is being generated by binary pulsars. A convincing theory of quantum gravity has to date to be formulated, but it will involve quanta referred to as gravitons which interact with everything. Einsteins theory of general relativity reproduced all the old results of Newton, but without even using the idea of weight. The core of general relativity is the interaction between space